Thank you to everyone who interacted with my last challenge! The replies were greatly appreciated.
My next challenge is for the math lovers. The triangle below, ABC is a right-angled triangle.
M is the mid-point of the hypotenuse AC.
You are given the lengths AB and BC (which are integers).
The task is to work out the angle MBC.
This is my solution:
// reading in 2 sides
ab: "I"$read0 0
bc: "I"$read0 0
// finding the distance
ac: sqrt((ab*ab)+(bc*bc))
bm: ac % 2.0
mc: bm
// equalizing the sides
b: mc
c: bm
a: bc
// where b=c
// finding the angle in radian
angle_b_radian: acos(a % (2*b))
// converting the radian to degree
round:{"F"$.Q.f[y]x}
angle_b_degree: round[((180 * angle_b_radian) % 3.141593);2]
answer: "i"$angle_b_degree
show angle_b_degreeI would love to see other approaches to this so if anyone has any comments or suggestions please let me know 😊
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