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lfox
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2021.11.23
2022.09.22
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Re: Q For Problems - Episode 1
2022.09.22
Nice, thanks. Somewhere in between then, maybe the join/distinct isn't very performant then
Re: Q For Problems - Episode 1
2022.09.22
Nice video, I didnt compare performance but here's what I came up with initially; f:{sum distinct (3*1+til n div 3),5*1+til (n:x-1) div 5} The same idea with the lists but I have joined and distinct on the lists rather than calculating for 15.
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