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kdb_newbie

I have the below trades table in my q session: q)meta trades c | t f a -----| ----- time | p sym | s g src | s g price| f size | i q) Then, why does it need each both for the sv function when x and y are joined already and then passed into sv: q)upda...

kdb_newbie

What do the below letters mean? https://code.kx.com/q/ref/deltas/ domain: b g x h i j e f c s p m d z n u v trange: i . i i i j e f . . n i i f n u v t Thank you! I had like to understand how do I read these when referring to the documentation.

kdb_newbie

Which form of iterator is being used here? Thank you! https://code.kx.com/q4m3/A_Built-in_Functions/#a88-ssr You can use the over iterator with ssr to replace multiple items. (ssr/)["results_%div_%dept.csv"; ("%div";"%dept"); ("banking";"m&a")]

kdb_newbie

kdb_newbie

https://code.kx.com/q/learn/reading/strings/#c_ns_n_nts {$["j";x in V]'[x;"_"]} / Case May I ask how does each both work here please?

kdb_newbie

Thank you very much! May I ask where is the documentation on "-1" used here?

kdb_newbie

I am trying to understand the .u.rep function in r.q:.u.rep: (.[;();:;].)each xShouldn't it apply the function to every item in x since we do "each"; it still needs the right-most dot to apply the function to each pair of xHere, x: x:((`trade;([]time...

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why sv needs ,' here?

domain and range

May I please know how the over iterator is being used here?

Why does the amend form of dot operator creates a projecttion like the line in .u.rep: (.[;();:;].)each x? Shouldn't it apply the function to every item in x since we do "each"? Thank you!

{$["j";x in V]'[x;"_"]} / Case

Re: May I please know how the over iterator is being used here?

Re: Why does the amend form of dot operator creates a projecttion like the line in .u.rep: (.[;();:;].)each x? Shouldn't it apply the function to every item in x since we do "each"? Thank y